Use the drop-down menus to match each formula to the satellite motion characteristic it is used to solve. ac = StartFraction v Superscript 2 Baseline over r EndFraction Fc = StartFraction m times v Superscript 2 Baseline over r EndFraction v = StartFraction 2 pi r over T EndFraction

good looking response

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

at right angles to each other