an object accepts a pressure of 2:00 p. m. on the ground object is kept above it then the dead pressure will become Dash

Correct question is;

An object exerts a pressure of 2 pa on the ground if another object of the same weight is kept above it then the net pressure will become

4 pa

Explanation:

We know that formula for pressure is;

P = Force/area

Where formula for force is;

F = mg

Thus;

P = mg/A

We are told P = 2 pa

Thus;

mg/A = 2

Now, when we add the same weight, our new Force is;

F_new = mg + mg = 2mg

Area remains the same A.

Thus, net pressure = F_new/A = 2mg/A

From earlier, we saw that mg/A = 2.

Thus;

net pressure = 2mg/A = 2 × 2 = 4 pa

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y