A sports car is accelerated from 0 car?
100 km per hour in 3 s. What is the acceleration of the?
A. 0.1g
100
B. 0.3 g
3s 1 1m 11h
160, 160m
C. 0.9 g
D. 3 g
23. [1 mark]

C, 0.9g

We know that 1 g = 9.8 m/s^2. So first we’ll need to convert 100 km/hr to m/s. So we can compare meters to meters and seconds to seconds (we’ll handle the s^2 soon).

100 km/hr * (1000 m)/(1 km) * (60 min)/(1 hr) * (60 sec)/(1 min) = 27.778 m/s.

We know that this car achieved this speed in 3 seconds. Since acceleration is change in velocity, and we know the velocity of the car changed from 0 to about 27.8 m/s in 3 seconds, we know that our acceleration is:
(27.8 m/s - 0 m/s) / (3 s) = 9.259 m/s^2.

Now to find how many g’s, we know that 1 g = 9.8 m/s^2. So we know that 9.259 m/s^2 / 9.8 m/s^2 = about 0.9. This will be 0.9 of 1 g, which is just 0.9 g.

Distance^2= yellow line ^2 (see picture) = 30^2 + 49^2so distance = squareroot of (300^2 +49^2)i dont know if this is how to solve it, but i cnt think of another way

The car would move to the right with 150 n of force. the 150 n of force from friction and air resistance slows the car from moving to the right with 300 n of force.