The nucleus in an iron atom has a radius of about 4.0 10-15 m and contains 26 protons. (a) What is the magnitude of the repulsive electrostatic force between two of the protons that are separated by 4.0 10-15 m?

The  repulsive electrostatic force between two of the protons is 14.4 N.

Explanation:

Given;

distance between the two protons, r = 4 x 10⁻¹⁵ m

charge of a proton, q = + 1.6 x 10⁻¹⁹ C

The repulsive electrostatic force between two of the protons is calculated by applying Coulomb's law;

Therefore, the  repulsive electrostatic force between two of the protons is 14.4 N.

i'm thinking more like energy

where are the vectors ?