g a 100 m3 container with 1/3 water with pressure of 100 MPa drops to 90 Mpa how much heat transfer is required to bring back to the initial condition

 Q = 3.33 108 J

Explanation:

This is an exercise in thermodynamics, specifically isobaric work

        W = V (- P₀)

They tell us that we have ⅓ of the volume of the container filled with water

        V = ⅓ 100

         V = 33.3 m³

let's calculate

        W = 33.3 (90-100) 10⁶

        W = - 3.33 10⁸ J

To bring the system to its initial condition if we use the first law of thermodynamics

            ΔE  = Q + W

as we return to the initial condition the change of internal energy (ΔE) is zero

          W = -Q

therefore the required heat is

         Q = 3.33 108 J

what is the question?

hi there!

your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

hope this ! ~