Two lamps rated 60W; 240V and 100W, 240Vrespectively are connected in series to a 240V power source. Calculate; a) The resistance of each lamp.
b) The effective resistance of the circuit.
c) The current passing the lamps. pls answer correctly

See the answers below.

Explanation:

The total power of the circuit is equal to the sum of the powers of each lamp.

Now we have a voltage source equal to 240 [V], so by means of the following equation we can find the current circulating in the circuit.

where:

P = power [W]

V = voltage [V]

I = current [amp]

So this is the answer for c) I = 0.67 [amp]

We know that the voltage of each lamp is 240 [V]. Therefore using ohm's law which is equal to the product of resistance by current we can find the voltage of each lamp.

a)

where:

V = voltage [V]

I = current [amp]

R = resistance [ohms]

Therefore we replace this equation in the first to have the current as a function of the resistance and not the voltage.

b)

The effective resistance of a series circuit is equal to the sum of the resistors connected in series.

3.2x10^7