The ground state of lithium (Z = 3) has two electrons in the 1s level and one in the 2s. Consider an excited state in which the outermost electron has been raised to the 3p level. Since the 3p wavefunctions are not very penetrating, you can estimate the energy of this electron by assuming it is completely outside both the other electrons. a. In this approximation what is the potential energy felt by the outermost electron?
b. In the same approximation write the formula for the energy of the outer electron if its principal quantum number is n.
c. Estimate the energy of the 3p electron in this way and compare with the observed value of −1.556 eV

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

i think they are all correct

explanation:

they seem good

vapour or gas assuming atmospheriv pressure