How far does a car travel in 30.0 s while its velocity is changing from 50.0 km/h to 80.0 km/h at a uniform rate of acceleration?

According to the question,

We know the relation,

→

or,

→  

Now,

The acceleration,

→

By substituting the values,

hence,

The distance traveled be:

→

Thus the above answer is right.

Find out more information about the distance here:

link

The car will travel 541.67 m

Explanation:

Constant Acceleration Motion

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

The relation between the initial and final speeds is:

Where:

vf  = Final speed

vo = Initial speed

a   = Acceleration

t   = Elapsed time

The acceleration can be calculated by solving for a:

And the distance traveled is:

The car travels during t=30 s, and its speed changes from vo=50 Km/h to vf=80 Km/h.

Let's convert the speeds to m/s. Recall 1 Km=1000 m and 1 h= 3600 s:

vo=50 Km/h * 1000/3600 = 13.89 m/s

vf=80 Km/h * 1000/3600 = 22.22 m/s

Calculating the acceleration:

Now for the distance:

The car will travel 541.67 m

answer: option c. i.e. electric current flowing “downhill” from the negative electrode to the positive electrode in a battery

explanation:

the water analogy to the circuits define the pipes (water flows) to the electric current. now, we know that the electric current flows from the positive terminal to the circuit (as shown in the diagram attached).

hence, option c is the correct answer.

attach the statements so i can answer : )