How far does a car travel in 30.0 s while its velocity is changing from 50.0 km/h to 80.0 km/h at a uniform rate of acceleration?

According to the question,

We know the relation,

→

or,

→  

Now,

The acceleration,

→

By substituting the values,

hence,

The distance traveled be:

→

Thus the above answer is right.

Find out more information about the distance here:

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The car will travel 541.67 m

Explanation:

Constant Acceleration Motion

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

The relation between the initial and final speeds is:

Where:

vf  = Final speed

vo = Initial speed

a   = Acceleration

t   = Elapsed time

The acceleration can be calculated by solving for a:

And the distance traveled is:

The car travels during t=30 s, and its speed changes from vo=50 Km/h to vf=80 Km/h.

Let's convert the speeds to m/s. Recall 1 Km=1000 m and 1 h= 3600 s:

vo=50 Km/h * 1000/3600 = 13.89 m/s

vf=80 Km/h * 1000/3600 = 22.22 m/s

Calculating the acceleration:

Now for the distance:

The car will travel 541.67 m

an enlarged virtual image

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get