A man is standing on the edge of a 20.0 m high cliff. He throws a rock horizontally with an initial velocity of 10.0 m/s. How long does it take to reach the ground? How far does the rock land from the base of the cliff?

d = 20.2 m

t = 2.02 s

Explanation:

Horizontal Motion

When an object is thrown horizontally with a speed v from a height h, it describes a curved path ruled by gravity until it hits the ground.

To calculate the time the object takes to hit the ground, we use the equation:

Note the time does not depend on the initial speed.

The range or maximum horizontal distance traveled by the object can be calculated as follows:

The man standing on the edge of the h=20 m cliff throws a rock with a horizontal speed of v=10 m/s.

The time taken by the rock to reach the ground is:

t = 2.02 s

Now for the horizontal range:

d = 20.2 m

28. evolution

29. environment, survive, offspring  

explanation:

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.