A woman of mass 44 kg jumps off the bow of a 69 kg canoe that is intially at rest.
If her velocity is 2.5 m/s to the right, what
is the velocity of the canoe after she jumps?
Answer in units of m/si.

v₃ = 1.59 [m/s]

Explanation:

In order to solve this problem, we must use the principle of conservation of linear momentum.

That is, the momentum is conserved before and after the jump.

Before the jump, we have the mass of the woman and the canoe without speed (at rest). After the jump you have the woman moving to the right and the canoe moving to the left.

where:

m₁ = mass of the woman = 44 [kg]

m₂ = mass of the canoe = 69 [kg]

v₁ = velocity of the canoe at rest = 0

v₂ = velocity of the woman after jumping = 2.5 [m/s]

v₃ = velocity of the canoe after jumping = [m/s]

answer: the metamorphic rocks are formed when they are exposed to high pressure and high temperatures. this happens when one of the earth's plates comes in contact with the other plate by traveling in opposite directions, straight into each other or slipping under one another. the friction that is caused by this activity results in   melting of rocks and when it cools they are known as metamorphic rocks. this process needs a controlled amount of pressure and temperature otherwise it may turn into magma.