At an ocean depth of 10.0m, a diver's lung capacity is 2.40L. The air temperature is 32.0°C and the pressure is 101.30 kPa. What is the volume of the diver's at the same depth, at a temperature of 21.0°C and a pressure of 141.20 kPa?

The volume of the diver's at the same depth, at a temperature of 21.0°C and a pressure of 141.20 kPa is 1.66 L

Explanation:

The combined gas equation is,

where,

= initial pressure of gas = 101.30 kPa

= final pressure of gas = 141.20 kPa

= initial volume of gas = 2.40 L

= final volume of gas = ?

= initial temperature of gas =

= final temperature of gas =

Now put all the given values in the above equation, we get:

The volume of the diver's at the same depth, at a temperature of 21.0°C and a pressure of 141.20 kPa is 1.66 L

they should be similar or the same

answerdmitry mendeleyev made a workable classification of the elements