Calculate the magnetic field strength needed on a 200-turn square loop 20.0 cm on a side to create a maximum torque of 300 N-m if the loop is carrying current of 25.0 A.

The magnetic field strength needed is 1.5 T.

Explanation:

Given;

number of turns, N = 200 turn

length of the each side of the square loop, L = 20 cm = 0.2 m

maximum torque created, τ = 300 N-m

current through the loop, I = 25 A

The maximum torque created in the is the loop is given by;

τ = NIBA

Where;

B is the magnetic field strength, which is calculated as;

Therefore, the magnetic field strength needed is 1.5 T.

when a device is used in a circuit in which the voltage is 81 v, the current flowing through the device is 3 a. what is the resistance of the device?

a. 27 ω

b. 40.5 a

c. 243 ω

d. 243 a

the correct answer is a. 27

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .