You have a 100 N object with a normal force of 100 N. You apply a 50 N push to the right, but a friend is hiding on the other side of the object and is also pushing with a force of 60 N. What is the net force on the object?

100.49N

Explanation:

First we must know that the normal force acts in the vertical direction;

The force required to push to the right and left acts in the horizontal direction;

Sum of force along the horizontal Fx = 50N - 60 N = -10N

Force along the vertical Fy = 100N

The net force on the object is calculated as;

F = √(Fx)² + (Fy)²

F = √(-10)² + (100)²

F = √100 + 10000

F = √10,100

F = 100.49N

Hence the net force on the object is 100.49N

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards