An alpha particle has mass m = 6.64×10−27 kg and a gold nucleus has mass M = 2.32×10−25 kg. If K = 15.0 MeV then what is the speed V as a fraction of c, and what proportion of the original energy is transferred to the gold nucleus?

The answer is a it is actually

stands for electromotive force and it is measured in volts. despite its name, it is not actually the force in the sense of being a "pushing" or "pulling" (not measured in newtons).an equation that relates emf,  ℰ,  to a battery's terminal voltage, v, current, i, and internal resistance, r, is    ℰ = v + irin this case, the emf can be interpreted as a voltage—a difference in electric potential.i would not say that it would be considered an energy. if emf can be defined as the energy/work per a unit charge from a battery or other electric source, then it is not strictly energy.