An object is at rest when it undergoes a constant acceleration of 13 m/s2 for 5.0 seconds.
How far will it have traveled during this time?

Hi there!

Find the distance traveled using the kinematic equation:

d = vi(t) + 1/2(a)(t²)

In this instance, vi = 0 because the object was initially at rest. Plug in the other values to solve:

d = 0t + 1/2(13)(5²)

d = 1/2(13)(25)

d = 162.5m

hypothesising or postulating

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.