A force F of strength 25 N acts on an object with a mass of 3 kg as it moves a distance of 10m. If F is perpendicular to 10m displacement the work it does is equal to

v 154.9= 0.9 length length s little over 154.9cm

a) the event horizon, singularity, and the chute located between the two.

98.4 m

explanation:

let s = distance up the plane  

then by conservation of energy  

1/2m(18.3)^2 = mg s sin(10)  

(18.3)^2 = 2g s sin(10)  

s = (18.3)^2/2gsin(10)  

= 98.39564526  

= 98.4 m