HURRY PLEASE Three resistors of 3.0 9, 8.0 2, and an unknown resistance are
connected in series across a 9.0-V battery. If the current through the unknown
resistance is measured to be 1 A, answer the following questions.
a. What is the current through the 3.0-Q resistor?
b. What is the equivalent resistance of the circuit?
c. What is the potential difference across the 3.0-0 resistor?

I think that the answer is the first or third one

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

okay i have so many questions. but the big one here is: um wt..f is this mess? ?