Page 3 of 6 2.
A dolphin is swimming under water at a constant speed of 4.50ms-1.
(a) The dolphin strikes the bottom of a floating ball so that the ball rises vertically upwards from
the surface of the water, as illustrated in Fig. 2.1.
h
path of
ball
height of
ball above
surface
ball
surface of water
speed 5.6 ms-11
Fig. 2.1
The ball leaves the water surface with speed 5.6 ms 1.
Assume that air resistance is negligible.
(0)
Calculate the maximum height reached by the ball above the surface of the water.

i wanna say it’s between b and d, leaning more towards b.

laticia draws the diagram below to show earth’s magnetic field.

answer

the arrows to the right of earth should point up.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s