Cammie wonders whether hydrogen bonds would form if water molecules had a linear shape, with the oxygen atom in between the two hydrogen atoms. Which statement best answers Cammie’s question?

* A straight molecule would not be able to form hydrogen bonds because the oxygen atom would pull electrons equally from both hydrogen atoms, and the molecule would have no polarity overall.
* A straight molecule would still be able to form hydrogen bonds because the hydrogen atom at one end would be slightly negative and the hydrogen atom on the other end would be slightly positive.
* A straight molecule would not be able to form hydrogen bonds because the electrons would be shared equally between the oxygen atom and the hydrogen atoms.
* A straight molecule would still be able to form hydrogen bonds because the oxygen atom would still pull harder on the shared electrons than the hydrogen atoms.

To understand the electric potential and electric field of a point charge in three dimensions consider a positive point charge q, located at the origin of three-dimensional space. throughout this problem, use k in place of 14? ? 0. part adue to symmetry, the electric field of a point charge at the origin must point from the origin. answer in one word. part bfind e(r), the magnitude of the electric field at distance r from the point charge q. express your answer in terms of r, k, and q. part cfind v(r), the electric potential at distance rfrom the point charge q. express your answer in terms of r, k, and q part dwhich of the following is the correct relationship between the magnitude of a radial electric field and its associated electric potential ? more than one answer may be correct for the particular case of a point charge at the origin, but you should choose the correct general relationship. a)e(r)=dv(r)drb)e(r)=v(r)rc)e(r)=? dv(r)drd)e(r)=? v(r)r