A wagon moving down the road has 2000 kg m/s of momentum. Then a 500-kg bag of feed with no velocity is added to the wagon. What is the new momentum of the wagon with the feed bag in kg m/s?

The new momentum of the wagon with the feed bag is (also) 2,000 kg·m/s

Explanation:

The given momentum of the wagon = 2000 kg·m/s

The mass of the added bag = 500 kg

The initial velocity of the bag of feed = 0 m/s

Therefore, by the conservation of momentum principle, we have;

The total initial momentum of the wagon and the bag of feed before the bad of feed is added to the wagon = The new momentum of the wagon with the feed bag

Which gives;

The total initial momentum of the wagon and the bag of feed before the bad of feed is added to the wagon  = 2,000 kg·m/s + 500 kg × 0 = 2,000 kg·m/s = The new momentum of the wagon with the feed bag

Therefore, the new momentum of the wagon with the feed bag = 2,000 kg·m/s.

increases it

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.