When you irradiate a metal with light of wavelength 417 nm in an investigation of the photoelectric effect, you discover that a potential difference of 1.15 V is needed to reduce the current to zero. What is the energy of a photon of this light in electron volts

E = 4.76 eV

Explanation:

It is given that,

Wavelength = 417 nm

Potential difference = 1.15 V

We need to find the energy of a photon of this light in electron volts. The energy of a photon is given by :

Where

h is Planck's constant, c is speed of light

We know that,

or

E = 4.76 eV

So, the energy of a photon is 4.76 eV.

the answer is a)

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