A 135 kg horizontal platform is a uniform disk of radius 1.95 m and can rotate about the vertical axis through its center. A 63.7 kg person stands on the platform at a distance of 1.05 m from the center, and a 30.1 kg dog sits on the platform near the person 1.33 m from the center. Find the moment of inertia of this system, consisting of the platform and its population, with respect to the axis.

the  moment of inertia is 380.14 kg-m^2

Explanation:

The computation of the moment of inertia is as follows:

The net moment of inertia is

= MR^2 ÷ 2 + m_p d_p^2 + m_d d_d^2

= 135 × 1.95^2 ÷2 + 63.7 ×  1.05^2 + 30.1 × 1.33^2

= 380.14 kg-m^2

hence, the  moment of inertia is 380.14 kg-m^2

We simply applied the above formula so that the correct value could come

And, the same is to be considered

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this is a good question! i'll do some research and come back when i have the answer!