A batter hits a ball at 25 m/a 37 degrees above the horizon. (Part A) how long is the ball in the air? (Part b) how far does it travel?

Explanation:

we know

v=u-gt

At max height v=0

uy=usin30

now,25sin37=gt

15.07/9.8=t

t=1.53s to reach max height now to come on ground it takes same time

so time taken t=3.07s

We know ,range=ucos37×t

=25cos37×3.07

max distance=61.3meter

c

explanation:

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer