Se coloca una tuerca con una llave, como muestra la figura, si el brazo r= 30 cm y el torque de apriete recomendado para la fuerza es de 30 Nxm, Cuàl debe ser el valor de la fuerza F aplicada?

F = 100 N

Explanation:

The torque is given by the expression

      τ = F x r

where bold letters indicate vectors, the magnitude of this expression is

     τ = F r sin θ

In general, when tightening a nut, the force is applied perpendicular to the arm, therefore  θ = 90 and sin 90 = 1

      τ = F r

      F = τ / r

calculate

      F = 30 / 0.30

      F = 100 N

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