Un bat de beisbol ejerce una fuerza promedio de 50n sobre una pelota durante 0.40s.¿ que impulso recibio la pelota tras ser bateada una pelota? De beisbol de 0.11 kg se separa de bat con una rapidez horizontal de 36m/s si el bat esta en contacto con la pelota or 0.5 s ¿cual es el valor de la fuerza horizontal promedio que ejerce el bat en la pelota?

A) I = 20 N s

,  B)   F = 7.92 N

Explanation:

A)  The momentum is

I = F Δt  

calculate  

I = 50 0.40  

I = 20 N s

B) The momentum is related to the change of the moment of the system  

I = Δp  

F Δt = m   - m v₀

in this case we must assume that the initial velocity is very small, vo = 0  

F = m v_{f} / Δt  

calculate  

F = 0.11 36 / 0.5  

F = 7.92 N

the bal will not change its velocity.

  the unit of the measure =

explanation:

  the property that is quantified by the energy needed per of material to raise the temperature by one.

  si unit of energy = joule (j)

  si unit of temperature = kelvin (k)

  si unit of mass of material = kilogram (kg)

the property that is quantified by the energy needed per of material to raise the temperature by one is called specific heat.

the unit of specific heat is