A gasoline engine absorbs 2 500 J of heat and performs 1 000 J of mechanical work in each cycle. The efficiency of the engine is:

The efficiency of the engine is 40 %

Explanation:

Given;

input energy, = 2500 J

output energy, = 1000 J

The efficiency of the engine is given as;

Efficiency = output energy / input energy

Efficiency = 1000 / 2500

Efficiency = 0.4

Efficiency(%) = 0.4 x 100%

Efficiency = 40 %

Therefore, the efficiency of the engine is 40 %

current flows in a wire