subject
Physics, 03.12.2020 22:40 danielboek

A 2100 lb (1 kg=2.2 lbs) car is using 4500 N of traction in order to move with a constant velocity of 67 mph (29.8 m/s). What is the acceleration of this 9300 N vehicle?

ansver
Answers: 2

Other questions on the subject: Physics

image
Physics, 21.06.2019 17:00, 001136843
Which energy transformation occurs in the core of a nuclear reactor? nuclear energy mechanical energy nuclear energy - thermal energy thermal energy -- nuclear energy mechanical energy - nuclear energy
Answers: 2
image
Physics, 21.06.2019 23:30, idjfjcjs584
Edward tolman explained the results of his study by theorizing that the rats were learning about the maze during every trial but they a. were agitated because other groups were getting reinforcement b. could not remember how to demonstrate it without reinforcement c. were not motivated to demonstrate it without reinforcement d. seemed to be too lazy to actually work without reinforcement
Answers: 3
image
Physics, 22.06.2019 04:20, gonzalesalexiaouv1bg
When considering gravity acceleration and the force of acceleration, what must be true? a. the direction of acceleration must be perpendicular to the direction of the force. b. the direction of the force and the direction of acceleration must be the same as each other. c. the direction of the force and the direction of acceleration must be opposite of each other. d. the mass of the body must be the same as the acceleration of the body.
Answers: 1
image
Physics, 22.06.2019 05:40, thomasalmo2014
Unpolarized light of intensity i_0=750w/m^2 is incident upon two polarizers. after passing through both polarizers the intensity is i_2=280w/m^2. (a) what is the intensity of the light after it passes through the first polarizer in w/m^2? (b) write an equation for the angle between the polarizers in terms of the initial (i_0) and final (i_2) intensities. (c) find the angle between the polarizers in degrees.
Answers: 3
You know the right answer?
A 2100 lb (1 kg=2.2 lbs) car is using 4500 N of traction in order to move with a constant velocity...

Questions in other subjects: