A Chevy Camaro drives straight off the top level off a parking garage at 13 m/s. If the car landed 90 meters away from the base of the parking garage, how high (height) was the top level? a200.64

b234.64

c34.64

d134.64

234.64 m

Explanation:

Using the formula for calculating range;

Range R = u√2H/g

u is the speed = 13m/s

H is the maximum height

g is the acceleration due to gravity = 9,8m/s²

R = 90m

Get the maximum height;

90 = 13√2H/9.8

90/13 = √2H/9.8

6.923 = √2H/9.8

square both sides

6.923² = 2H/9.8

469.698 = 2H

H = 469.698/2

H = 234.64

Hence the top level was 234.64 m high.

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