If 32 g of copper(II) sulfate are dissolved in 100 g of water at 20°C, is the solution produced saturated, unsaturated, or supersaturated?

If we now heat the mixture to 50 °C, the remaining 9 g of glucose will dissolve. At the new temperature, the solubility limit in 100 mL of water is 244 g glucose. With only 100 g of glucose dissolved, the solution is now unsaturated.
If we next cool the mixture back to 25 °C, 9 g of glucose should precipitate from solution.
If glucose crystals do not form, the system has more dissolved glucose (100 g) than it can hold at 25 °C (91 g). We have a supersaturated solution.
The first step in the formation of crystals is nucleation. This is when the solute molecules arrange themselves to form crystals.
Sometimes this happens at once. If it doesn't, we have a supersaturated solution. This is an unstable situation.
A piece of dust or a small crystal of the solute, a seed crystal, provides a template for crystallization of the excess solute. The excess solute starts to form crystals on the nuclei.

A., d., and f i think

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