How much energy is required to move a 1000 kg object from the Earth's surface to an altitude twice the Earth's radius?

1.250 × 10¹¹ J

Explanation:

Step 1: Given and required data

Step 2: Calculate the energy required to move the object

The energy required to move the object from the Earth's surface to an altitude twice the Earth's radius is equal to the change in the gravitational potential energy (G) between both levels. We will use the following expression.

E = G₂ - G₁

E = m × g × h₂ - m × g × h₁

where h is the altitude (h₁ = 0)

E = m × g × h₂

E = 1000 kg × 9.807 m/s² × 2 × 6.371 × 10⁶ m

E = 1.250 × 10¹¹ J

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.