The angular acceleration of a wheel, as a function of time, is α = 5.0 t2 - 8.5 t, where α is in rad/s2 and t is in seconds. If the wheel starts from rest (θ = 0, ω = 0, at t = 0), determine a formula for a) the angular velocity ω as a function of time
b) the angular position θ as a function of time
c) evaluate ω at t = 4.0 s
d) evaluate θ at t = 4.0 s

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Initial velocity,  u = 4.9 m/sfinal velocity = v m/sinitial height,  h₁ =  245 m    final height, h₂ = 0a = -9.8  m/s²time taken = t secondss = ut + 0.5at²⇒  (h₂-h₁) = ut + 0.5at²⇒  0-245 = 4.9t + 0.5×(-9.8)×t²⇒ -245 = 4.9t - 4.9t²⇒ 4.9t² -4.9t -245 =0solving it, we get   t = 7.59sv  = u +  at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/svelocity is  69.48 m/s downward