Physics, 29.11.2020 14:40 xxaurorabluexx

During a tennis match, a player serves the ball at 23.6 m/s, with the center of the ball leaving the racquet horizontally 2.37 m above the court surface. The net is 12 m away and 0.90 m high. When the ball reaches the net, (a) does the ball clear it and
(b) what is the distance between the center of the ball and the top of the net? Suppose that, instead, the ball is served as before but now it leaves the racquet at 5.00° below the horizontal. When the ball reaches the net,
(c) does the ball clear it and
(d) what now is the distance between the center of the ball and the top of the net?

Answers: 1

Show answers

Answers

Answer from: lizarroyo

Yes it clears

$b= 0.19 \ m$

No it does not clear

$z= 0.86 \ m$

Explanation:

From the question we are told that

The speed at which the player serves the ball is $v = 23.6 \ m/s$

The height of the ball above the ground is $h = 2.3 7 \ m$

The distance of the net is $d = 12 \ m$

The height of the net is $H = 0.9 \ m$

Generally the time taken for the ball to reach the net is mathematically represented as

$t = \frac{d}{v}$

=> $t = \frac{12}{23.6}$

=> $t = 0.508 \ s$

Generally the change in height of the ball after t is mathematically represented as

$\Delta h = ut + \frac{1}{2} gt^2$

Here u is the initial velocity which is zero given that the ball was at rest initially

$\Delta h = 0* t + \frac{1}{2} * 9.8 * 0.50 8^2$

=> $\Delta h =1.28 \ m$

Generally the new height of the ball is mathematically evaluated as

$s= h-\Delta h$

=> s = 2.37 - 1.28

=> $s = 1.09 \ m$

From the value obtained we see that s H hence the ball clears the net

Generally the distance between the center of the ball and the top of the net is mathematically represented as

b = s - H

=> b = 1.09 - 0.90

=> $b= 0.19 \ m$

Given that the ball makes an angle of 5^o with the horizontal , the velocity along the x-axis is

v_x = v cos(5)

=> v_x = 23.6 cos(5)

=> $v_x = 23.5 \ m/s$

The velocity along the y-axis is

v_y = v sin(5)

=> v_y = 23.6 sin(5)

=> $v_y = 2.06 \ m/s$

Generally the time taken for the ball to reach the net is

$t = \frac{d}{v_x}$

=> $t = \frac{12}{23.5}$

=> $t =0.508 \ s$

Generally the change in height of the ball after t seconds is

$c = v_yt + \frac{1}{2}gt^2$

=> $c = 2.06 * 0.508 + \frac{1}{2}* 9.8 * 0.508 ^2$

=> c = 2.33

Generally the new height of the ball after time t seconds is

e = h - c

=> e = 2.37 - 2.33

=> $e = 0.04 \ m$

From the value obtained we see that e < H hence the ball does not clear the net

Generally the distance between the center of the ball and the top of the net is mathematically represented as

z = H-e

=> z = 0.90 - 0.04

=> $z= 0.86 \ m$

Answer from: Quest

Iread this book last year so take this with a grain of salt.gene jumps from the tree to compete with finny due to the fact that gene is always trying to do better than finny. he is put under the grasp of peer pressure due to finny almost forcing him to do this. ever since he first jumped finny kept pressuring him to jump since he thought gene enjoyed jumping.rather than uses this answer you should probably just reread chapters 3-4

Answer from: Quest

Uncle grandma

Other questions on the subject: Physics

Physics, 22.06.2019 00:30, chayaharroch03

Imagine you work as a consultant, and your daily job involves listening to the constructive criticism of others. as part of your job, you must listen to opposing viewpoints to make important decisions. in this activity, you are a consulting dam engineer. you must make a decision about four different dams; should they be repaired, taken down, or left alone? you will listen to contrasting opinions about what should be done with the dams before you make the final decision. as the consulting dam engineer, what do you decide to do with this dam? explain your reasoning. by making your decision, did you support the opinions of the mayor and/or the dam safety official? why or why not? (site 1)

Answers: 1

continue

Physics, 22.06.2019 06:00, tylorroundy

Aball is thrown upward. at a height of 10 meters above the ground, the ball has a potential energy of 50 joules (with the potential energy equal to zero at ground level) and is moving upward with a kinetic energy of 50 joules. what is the maximum height h reached by the ball? consider air friction to be negligible. 1. h ≈ 10 m 2. h ≈ 50 m 3. h ≈ 30 m 4. h ≈ 40 m 5. h ≈ 20 m 003 10.0 points which of the two object shown below has the greatest kinetic energy? a m b 1 2 m v 2v 1. kinetic energies are the same. 2. a 3. b 4. unable to determine. 004 10.0 points tim, with mass 74.6 kg, climbs a gymnasium rope a distance of 3.1 m. the acceleration of gravity is 9.8 m/s 2 . how much potential energy does tim gain? answer in units of j. 005 10.0 points a car is moving at 64 miles per hour. the kinetic energy of that car is 5 × 105 j. how much energy does the same car have when it moves at 111 miles per hour? answer in units of j. 006 10.0 points an 102 kg man climbs up a 1 m high flight of stairs. the acceleration of gravity is 9.81 m/s 2 . w

Answers: 3

continue

Physics, 22.06.2019 12:30, phancharamachasm

How do the kidneys affect homeostasis

Answers: 1

continue

Physics, 22.06.2019 19:50, nadiareese

Aleaky 10-kg bucket is lifted from the ground to a height of 15 m at a constant speed with a rope that weighs 0.7 kg/m. initially the bucket contains 45 kg of water, but the water leaks at a constant rate and finishes draining just as the bucket reaches the 15-m level. find the work done. (use 9.8 m/s2 for g.) show how to approximate the required work by a riemann sum. (let x be the height in meters above the ground. enter xi* as xi.) lim n → ∞ n (9.8)(45−3 xi) i = 1 δx express the work as an integral. 0 dx evaluate the integral. (round your answer to the nearest integer.) j

Answers: 3

continue

You know the right answer?

During a tennis match, a player serves the ball at 23.6 m/s, with the center of the ball leaving the...