A sample of the mineral cinnabar has a mass of 251.1g and a volume of 31.0 cm3. What is the density of cinnabar?

8.1 g/cm³

Explanation:

The following data were obtained from the question:

Mass of cinnabar = 251.1 g

Volume of cinnabar = 31 cm³

Density of cinnabar =?

Density of a substance is simply defined as the mass of the substance per unit volume of the substance. It can be represented mathematically as:

Density = mass / volume

Using the above equation, we can obtain the density of the cinnabar as follow:

Mass of cinnabar = 251.1 g

Volume of cinnabar = 31 cm³

Density of cinnabar =?

Density = mass / volume

Density of cinnabar = 251.1 / 31

Density of cinnabar = 8.1 g/cm³

Thus, the density of the cannabar is 8.1 g/cm³

answer;

d. are made mostly of liquid

explanation;

-the general   composition and structure planets includes; they have a thick gas and liquid layer covering a small,solid core. mostly the gases are hydrogen and helium atmosphere and layers of liquid hydrogen. for instance neptune and uranus are examples of the outer planets, they have a core covered by ice and ammonia.

-neptune's atmosphere is hydrogen and helium with a bit of methane so there is no oxygen to breath and the interior is made up of frozen water and ammonia with a rock and iron core. thus, there is no liquid water or solid surface to survive.

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west