Imagine que su primo Morton baja en patineta por una rampa curva en un parque. Tratando a Morton y su patineta como una partícula, esta describe un cuarto de circulo de Radio= 3.00 m (ver figura) La masa total de Morton y su patineta es de 33 Kg. El parte del reposo y no hay fricción. Calcule su rapidez en la base de la rampa.

Explanation:

We can solve this problem using the principle of conservation of energy.

Starting point. For higher up the ramp

          Em₀ = U = m g h

where h is the height of the ramp h = 3.00 m

Final point. For low

          Em_{f} = K = ½ m v²

as there is no friction the mechanical energy is conserved

          Em₀ =

          m g h = ½ m v²

          v = √ (2g h)

let's calculate

         v = √(2 9.8 3.00)

         v = 7.668 m / s

the answer is 3.1 his answer is wrong mines is right

i am pretty sure it is c because when people are closer together, they cannot move as freely. picture being in a mostly full elevator, for instance. the people are right next to you, and you can barely move.