A hollow ball with a diameter of 3.81 cm has an average density of 0.0842 g/cm3. What force must be applied to hold it stationary while it is completely submerged under water? (Enter the magnitude in N, and select the direction from the options given.)

To determine the force that must be applied to the hollow ball to hold it stationary while it is completely submerged under water is 0.2243 Newton.

Given the following data:

Density of water = 1000

Conversion:

Diameter of hollow ball = 3.81 centimeters to meters =

Density of hollow ball = 0.0842 to =

To determine the force that must be applied to the hollow ball to hold it stationary while it is completely submerged under water:

First of all, we would calculate the volume of the hollow ball by using the formula:

Next, we would find the force required for water and the hollow ball:

For water:

For hollow ball:

Now, we can find the force that must be applied to the hollow ball:

Force = 0.2243 Newton

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0.26

Explanation:

Given that :

Diameter of ball = 3.81 cm = 3.81/100 = 0.0381 m

Radius (r) = 0.0381 / 2 = 0.01905 m

Average density of ball (Db) = 0.0842 g/cm³ = (0.0842 / 1000)kg / 10^-6 = 0.0842/ 1000 * 10^6 = 84.2kg/m³

Density of water (Dw) = 1000kg/m³

Volume of hollow ball: (4/3) * pi * r³

V = (4/3) * π * 0.01905^3

V = 0.0000289583 m³

Required force = (Dw * V * g) - (Db * V * g)

= (1000 * 0.0000289583 * 9.8) - (84.2 * 0.0000289583 * 9.8)

= 0.259896109172

= 0.2598 N

gets less

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