A proton undergoes an acceleration of 2.00 × 107 ms2 for 3.00 ms before being released into a magnetic field. In the field, the proton travels a circular path of radius 1.00 cm at a constant speed. How long does it take for the proton to travel around the circular path three and a half times? What is the average velocity of the proton for the circular part of this motion?

less than one you can't create energy

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day