The Young’s modulus for steel is 2.0 x 10 11 N/m 2 and the interatomic spacing is 2.6A . Find the increase in inter atomic spacing, when a steel wire is subjected to a stress of 5 x 10 9 N/m

Increase in Atomic Spacing = 6.5 x 10⁻¹² m = 6.5 pm

Explanation:

The young's modulus of a material is given by the following formula:

Young's Modulus = Stress/Strain

2 x 10¹¹ N/m² = (5 x 10⁹ N/m²)/Strain

Strain = (5 x 10⁹ N/m²)/(2 x 10¹¹ N/m²)

Strain = 0.025

Now, the formula for the strain in the steel wire can be written in terms of atomic spacing as follows:

Strain = Increase in Atomic Spacing/Initial Atomic Spacing

0.025 = Increase in Atomic Spacing/2.6 °A

Increase in Atomic Spacing = (0.025)(2.6 x 10⁻¹⁰ m)

Increase in Atomic Spacing = 6.5 x 10⁻¹² m = 6.5 pm

(75°f − 32) × 5/9 = 23.889°c

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.