You are piloting a helicopter which is rising vertically at a uniform velocity of 14.70 m/s. When you reach 196.00 m, you see Barney (Uh-oh). A large object is projected with a horizontal velocity of 8.50 m/s from the rising helicopter. When does the ball reach Barney's head if he is standing in a hole with his head at ground level?

The ball reaches Barney  head in  

Explanation:

From the question we are told that

 The rise velocity is  

  The height considered is

   The horizontal velocity of the large object is  

Generally from kinematic equation  

Here s is the distance of the object from Barney head ,

        u is the velocity of the object along the vertical axis which is equal but opposite to the velocity of the helicopter

So  

So

=  

Solving the above equation using quadratic formula  

    The value of  t obtained is  

c. newton's third law of motion

dang that balls went far