Two girls, one of mass 40kg and the other of mass 60kg, are standing side by side in the middle of a frozen pond. One pushes the other with a force of 360 N for 0.10s. The ice is essentially frictionless.
a) What is each girl's acceleration?
b) What velocity will each girl acquire in the 0.10 s that the force is acting?
c) How far will each girl move during the same time period?

(a) What is each girl's acceleration?

Mg1-40kg Mg2-60kg Fa-360N T-0.10s

F=ma F/m=a 360N/40kg=a =9m/s^2 360N/60kg=-6m/s^2

(b) What velocity will each girl acquire in the 0.20s that the force is acting?

Vf=Vi+at =0+ 9m/s^2(0.10s)^2 = 0.9m/s

Vf=0+(-6m/s^2)(0.10s) = -0.60m/s

(c) How far will each girl move during the same time period?

d=Vi(t)+1/2(a)(t)^2 +1/2(9m/s^2)(0.10)^2 = 4.5 x10 ^-2 m

D=1/2(-6m/s^2)(0.10)^2 = -3.0 x 10 ^-2 m

Explanation:

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