A proton moves at a speed of 850 m/s in a direction perpendicular to a magnetic field with a magnitude of 0.70 T. What is the magnitude of the magnetic force on the proton?

The magnitude of the magnetic force on the proton is 9.532 x 10⁻¹⁷ N

Explanation:

Given;

speed of proton, v = 850 m/s

magnitude of magnetic field, B = 0.7 T

Charge of proton, q = 1.602 x 10⁻¹⁹ C

The magnitude of the magnetic force on the proton;

F = qvB

F = ( 1.602 x 10⁻¹⁹)(850)(0.7)

F = 9.532 x 10⁻¹⁷ N.

Therefore, the magnitude of the magnetic force on the proton is 9.532 x 10⁻¹⁷ N

0.3x0.21x0.08kg=mass 1 sheet

mass 500 = 500xmass 1

volume pile = 0.3x0.2x0.048

density=mass/volume= 500xmass 1/0.3x0.2x0.048

v patient student

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6