Calculate the average atomic mass of caarbon given the following information: Carbon-12 12.000 amu 98.89% Carbon-12 13.003 amu 1.11%

12.01

Explanation:

Given parameters:

Abundance of C-12  = 98.89%

mass of isotope  = 12amu

Abundance of C - 12  = 1.11%

mass of isotope  = 13.003

Unknown:

Average atomic mass of carbon  = ?

Solution:

The average atomic mass ;

R.A.M  = (mass of isotope x abundance of isotope)-12 + (mass of isotope x abundance of isotope)- 13

Insert the parameters and solve;

R.A.M  =( 12  x 98.89%)  + (1.11% x 13.003)

 R.A.M = 11.87 + 0.14 = 12.01

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz