Physics, 19.11.2020 21:40 rhlalbin

Math Practice: Cart A loaded with blocks (600g) moving left at 0.7m/s hits stationary cart B (200g). After the collision, both carts move left, Cart A at speed 0.27m/s.

What is the velocity of cart B after the collision? Show your work.

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Answer from: roneesmith2016

The velocity of cart B after the collision is 1.29 m/s.

Explanation:

We can find the velocity of cart B by conservation of linear momentum:

$p_{i} = p_{f}$

$m_{A}v_{A_{i}} + m_{B}v_{B_{i}} = m_{A}v_{A_{f}} + m_{B}v_{B_{f}}$

Where:

$m_{A}$ is the mass of cart A = 600 g = 0.6 kg

$m_{B}$ is the mass of cart B = 200 g = 0.2 kg

$v_{A_{i}}$ is the inital velocity of cart A = 0.7 m/s

$v_{A_{f}}$ is the final velocity of cart A = 0.27 m/s

$v_{B_{i}}$ is the initial velocity of cart B = 0

$v_{B_{f}}$ is the final velocity of cart B =?

Taking the left direction as the positive horizontal direction:

$0.6 kg*0.7 m/s + 0 = 0.6 kg*0.27 m/s + 0.2 kg*v_{B_{f}}$

$v_{B_{f}} = 1.29 m/s$

Therefore, the velocity of cart B after the collision is 1.29 m/s.

I hope it helps you!

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Math Practice: Cart A loaded with blocks (600g) moving left at 0.7m/s hits stationary cart B (200g)....