Un automóvil mantiene una aceleración uniforme de 7 m/s2. Si su velocidad inicial era de 6 m/s. Su velocidad en m/s después de 5 s es de

i need with 1.3.2 investigate cycling o2 and co2 apex

we need to see it

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j