A 7.5 Kg cannon ball leaves a canon with a speed of 185 meters per second. Find the average net force applied to the ball is the canon muzzle is 3.6 meters long

F = 35651 [N]

Explanation:

To solve this problem we must use the following equation of kinematics

where:

Vf = final velocity = 185 [m/s]

Vo = initial velocity = 0 (starts from the rest)

a = acceleration [m/s²]

x = distance = 3.6 [m]

Now we can find the acceleration.

185² = 0 + 2*a*3.6

34225 = 7.2*a

a = 4753.47 [m/s²]

Now we must use Newton's second law which tells us that the total force on a body is equal to the product of mass by acceleration.

F = m*a

where:

m = mass = 7.5 [kg]

F = force [N] (units of Newtons)

F = 7.5*4753.47

F = 35651 [N]

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever

a) electrical > light, sound, and thermal< < < <

) the mechanical energy of the firefighter moving.< < < < a) electrical > light, sound, and thermal< < < <

c) both a and b.