An apple is dropped from rest. A. Calculate the vertical velocity of the apple at 2.5 seconds? B. Calculate how far the apple has fallen in 2.5 seconds?

A. 24.5 m/s

B. 30.63 m

Explanation:

A. Determination of the vertical velocity of the apple.

Initial velocity (u) =?

Time (t) = 2.5 s

Acceleration due to gravity (g) = 9.8 m/s²

Vertical velocity (v) =?

v = u + gt

v = 0 + (9.8 × 2.5)

v = 0 + 24.5

v = 24.5 m/s

Thus, the vertical velocity of the apple is 24.5 m/s.

B. Determination of how far the apple has fallen.

Time (t) = 2.5 s

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) =.?

h = ½gt²

h = ½ × 9.8 × 2.5²

h = 4.9 × 6.25

h = 30.63 m

Thus, the apple has fallen 30.63 m in 2.5 s.

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)