A baseball is thrown off of a building with an initial velocity of 17 m/s and lands 2.3 seconds later. How tall is the building?

h = 65.021 m

Explanation:

Given that,

Initial velocity of a baseball, u = 17 m/s

It lands 2.3 seconds later.

We need to find the height of the building. Let it is h. It can be calculated using second equation of motion as follows :

here, a = g

So, the building is 65.021 m tall.

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