If a racket strikes a ball (m = 100 g) with a force of 2000 n for 0.3 s., calculate the velocity the ball has as it leaves the racket, assuming it starts from rest.
v = m/s

6 m/s
60 m/s
600 m/s
6000 m/s

By impulse definition we have to:

F * Δt = m * Δv

Where,

F: Applied force

Δt: change in time

m: mass

Δv: change in speed

Substituting values we have:

2000 * (0.3 - 0) = (0.1) * (v - 0)

From here, we clear the speed.

We have then:

2000 * 0.3 = 0.1v

v = (2000 * 0.3) / (0.1)

v = 6000 m / s

the velocity the ball has as it leaves the racket, assuming it starts from rest is:

v = 6000 m / s

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west