Consider a compact car that is being driven at 98 km/h.
The acceleration of gravity is 9.8 m/s2.
From what height would the car have to be
dropped to have the same kinetic energy?
Answer in units of m.

The height from which the car would have to be  dropped to have the same kinetic energy is 37.81 meters.

Given the following data:

To find the height from which the car would have to be  dropped to have the same kinetic energy:

First of all, we would convert the value of velocity in km/h to m/s.

Conversion:

Applying the law of conservation of energy:

Substituting the given parameters into the formula, we have;

Height, h = 37.81 meters

Read more: link

Height h = 37.8 m

Explanation:

Given :

Velocity of car (v) = 98 km / h

Acceleration of gravity = 9.8 m/s²

Computation:

Acceleration of gravity = 9.8 m/s²

Acceleration of gravity = (98)(1,000 m / 3,600 s)

Acceleration of gravity = 27.22 m/s

By using law of conservation of energy ;

(1/2)mv² = mgh

h = v² / 2g

h = 27.22² / 2(9.8)

Height h = 37.8 m

first thing first of the answer is with technology. second thing second thing is that the big bang theory did not happened u see they say it did but what they dont realize is that like dinasures are still a round they might deny it but they and look at these 12 foot human skelteons they find lets see didnt the bible say something about giants. hope this peace.