Find the tension in the two ropes that are holding the 2.9 kg object in place. Rope 1 makes an angle of 51.3° with respect to the vertical. Rope 2 is pulling horizontally.

Explanation:

Let the tension in horizontal rope be T₁ and in the other rope be T₂ which is making angle of 51.3⁰

The vertical component of tension T₂ will balance the weight .

= T₂ cos 51.3 = 2.9 x 9.8

T₂ = 2.9 x 9.8  / cos 51.3

= 28.42 / .625

= 45.47 N

The horizontal component of T₂ will balance T₁

T₂ sin 51.3 = T₁

45.47 sin 51.3 = T₁

T₁ = 35.48 N .

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

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