A 4 kg jug of juice is pulled forward across a horizontal breakfast table, by a 12 N forward-directed force. A frictional force also impedes the jug's motion. What is the coefficient of kinetic friction between the table and jug, if the jug accelerates to the right at 2 m/s^2 ? A 0.08
B 0.1
C 0.2
D 0.3

Explanation:

According to equation of motion;

\sum F = ma

m is the mass of the body

a is the acceleration

\sum F = Fm - Ff (along the horizontal)

Fm is the moving force

Ff is the frictional force

Given;

Fm = 12N

Ff = nR = nmg

Ff = n(4)(9.8)

Ff = 39.2n

Substitute the given value into the expression above;

Fm - Ff = ma

12 - 39.2n = 4(2)

-39.2n = 8-12

-39.2n = -4

n = 4/39.2

n = 0.1

Hence the coefficient of kinetic friction between the table and jug is 0.1

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2